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Library · hunts/rh_moonshot/probe_tower/NOTES.md

probe_tower: probes of growing degree in the 7/8 assembly

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Hunt #150 (rh_moonshot), mechanism 6. 2026-10-21. Status: constructed and pushed to a located obstruction; not challenged yet; unreviewed by any person. Nothing here is a result until the case log in hunts/README.md says how this hunt ended. Files produced on branch hunt/rh-moonshot: tower_template.py (the arithmetic), test_probe_tower.py (the pins), results_probe_tower.json (one run of the report), RUNS.md, this page.

Grades, as in the hunt's MISSION.md: cited (a line of a source, quoted and checked against the pinned file by verify_citations, or a primary source read at the stated place), derived (algebra done here, checked in exact rational arithmetic, with sympy for statements symbolic in k; every derivation here is self-reviewed only), inferred (a reading that no computation here checks), measured (one floating route, mpmath). Nothing here is hardened or kernel-checked. A composite claim takes the grade of its weakest step. The paper is OpenAI, The Quasi-Riemann Hypothesis, 2026-09-30, github.com/openai/math at adc7f124, read by line number from <cache>/openai-math-adc7f124/paper.tex, SHA-256 42a5ee0febca59fd1def55cfd6c6808c322ef4237d7726303ea52f711deac6a3 (49 cited lines, all found on their stated lines).

0. The answer

  1. The tower goes the wrong way. In the paper the comparison pole sits at z = 1/6 because the row characters are sextic: Poisson frequencies are u a^6 (line 3758), the sum over a is zeta_F(6z) (line 4045), and its pole at 1/6 is the principal residue (line 4071). Replacing the order 6 by k where sixth powers are counted, and holding every other estimate at the paper's form, the abscissa is sigma_0(k) = 1 - 1/k + (M - 2 ell)/(2k) (derived; the k-reading is inferred). For every admissible geometry it is strictly increasing in k, with sigma_0(k + 1) - sigma_0(k) = (2 - (M - 2 ell))/(2k(k + 1)) > 0, and it tends to 1. A tower of probes of growing degree drives the abscissa toward 1, not toward 1/2.
  2. No order reaches 1/2, and the best order is the smallest. The dual-length condition alone gives sigma_0(k) >= 1 - 2/k (above 1/2 for k >= 5); with the floor rows counted in full, which is what perfect row counts give, sigma_0(k) >= 1 - 4/(5k) in the limit delta_0 -> 0 and 1 - 25/(32k) at the paper's floor bin (derived, exact LPs with dual multipliers, symbolic in k). The infimum over all orders k >= 2 is 3/5, at k = 2, for which no system exists.
  3. The formal order k = 1 is RH itself. At k = 1 (no twist: every frequency is principal) the balanced geometry gives sigma_0 = 1/2 exactly, and the direct bound it asks for is square-root cancellation in the Moebius sum, Littlewood's RH-equivalent condition. The template interpolates between that restatement of RH (k = 1) and the trivial bound (k -> infinity): the twist buys a provable direct bound and pays for it with the density 1/k of k-th powers among the frequencies.
  4. The large-k estimates. None needs to fail for the tower to fail. Of the two named candidates: the large sieve of degree k does not degrade (Blomer, Goldmakher and Louvel's Theorem 1.3 has the same M + N + (MN)^(2/3) for every n >= 3, read here from the arXiv source); the theta coefficients at squarefree indices are undetermined over number fields for n >= 4 and, over F_13[T] at n = 4, exist but are not multiplicative (hunt #148, uncommitted). That second failure closes the small-k doors (k = 4, 5), the only direction that helps, not the tower.
  5. The step that reads the Euler product is the same at every k: the principal row is linear in the target's coefficients and carries their Moebius-weighted squarefree sum (line 3967 supplies mu(c)), which the criterion needs as H/L with sup |H - 1| <= 1/2 (line 413). DH fails it at its zero 0.808517 + 85.699348i (|H - 1| = 1.0000, measured) and, for every finite deletion set, on every half-plane Re s > sigma_0 with sigma_0 < 1 (Saias and Weingartner, cited); Epstein (1,1,6) fails it at 0.953260 + 16.290216i (measured); W_a passes it at its own zero 3/4 + 14.1347i (|H_W - 1| = 0.236 with nothing deleted, measured) and is held off by unitarity in the direct bound, which moves its template target up by exactly 1/4.

Disposition: restricted class obstructed (section 9), with the mission's tower premise refuted inside that class.

1. Target and its relation to RH

Target. A sequence of probes P_k, k = k_1 < k_2 < ..., each verifying the hypotheses of the paper's continuation criterion (Proposition 2.1, lines 400-432) unconditionally at a boundary sigma_0(k), for every primitive finite-order Hecke character of its field, with sigma_0(k) -> 1/2. The Dirichlet transfer (the quadratic transfer proposition, line 6705) then gives zeta(s) != 0 for Re s > sigma_0(k) for every k, so zeta has no zero with Re s > 1/2, and the functional equation places every nontrivial zero on Re s = 1/2: the target implies RH (indeed GRH for Dirichlet L-functions). It is not an RH equivalent with a new estimate attached; the all-k step is the whole content, as the mission says. The question this mechanism had to answer is whether any natural tower makes the all-k step plausible.

2. The construction: the order-k template

2.1 Where the 6 enters (cited) and the reading of it as k (inferred)

constantvalue at k = 6linesorder-k form
Poisson frequencies u a^6, u sixth-power-freea^63758a^k
principal pole of zeta_F(6z)z* = 1/64045, 4071z* = 1/k
slot weight q_p^(z* - 1), normaliser Z^(-ell z*)q_p^(-5/6), Z^(-ell/6)15563, 15576q_p^(1/k - 1), Z^(-ell/k)
Gram exceptional frequencies a_1^6 e, counted K^(1/6)P_a^(1/6)8353, 8535, 8541P_a^(1/k)
the same after Cauchy-Schwarz, P_a = Z^bZ^(b/12)8570, 8619Z^(b/(2k))

That each of these sixes is the order k of the row characters is a reading (inferred), the same one hunt #136's probe lane makes (PROBE.md there, uncommitted, read). Everything else is held at the paper's form: the reflected energy, the dual length M + ell <= 1 (line 8246; that M + ell <= 1 suffices for a general geometry is hunt #134's reading, inferred), the floor-row exponent (lines 15729-15734, 15843-15847), the contour Re z = 17/50 (line 15742), the Euler regions (lines 4054-4056).

2.2 The formulas (derived)

With l_x = (M - b)/2, l_y = (M + b)/2, h = 1 - l_x + ell (line 5586), and z* = 1/k:

2.3 Reproduction at k = 6 (cited values rebuilt exactly)

Part I (ell, M, b) = (0, 1, 0): c = -2/3, low exponent 1/4, sigma_0 = 11/12 (lines 190, 509-510, 3717). Part II (1/6, 5/6, 1/8): (l_x, l_y, h) = (17/48, 23/48, 13/16), c = -11/16, low exponent 3/16, sigma_0 = 7/8 (lines 191, 514-515, 6860-6864, 8641-8642), C_0 = -1/48 and the floor value -7/1200 (lines 15734, 15847). For random geometries at k = 6 the target equals hunt #134's 5/6 + (M - 2 ell)/12.

What the reproduction does not pin. A pole read as k/36 also equals 1/6 at k = 6 and reproduces every constant above, yet makes sigma_0 decrease in k (test_planted_fault_a_wrong_k_reading_passes_k6_but_reverses_the_tower). The direction of the tower therefore rests on the structural reading "pole = 1/(character order)", which comes from lines 3758 and 4045 (the sum over the k-th power part a^k of the frequency is zeta_F(kz)), not from any reproduced number. Grade of the direction: inferred reading, derived algebra.

3. The tower question

3.1 Direction (derived)

sigma_0(k) = 1 - (2 - m)/(2k) with m = M - 2 ell. Every admissible geometry has m <= M <= 1, so 2 - m >= 1 > 0 and

sigma_0(k + 1) - sigma_0(k) = (2 - m) / (2 k (k + 1)) > 0, 1 - sigma_0(k) <= 2/k.

At the paper's geometry the increment from k = 6 to 7 is 1/56, and sigma_0(k) = 1 - 3/(4k): 7/8, 25/28, 29/32, 15/16, 31/32 at k = 6, 7, 8, 12, 24. The mechanism behind it: the principal frequencies of an order-k twist are the k-th powers, whose number up to height T is about T^(1/k); the signal is proportional to that density, so it weakens as k grows.

3.2 Walls per order (derived; exact LPs over (ell, M, b), dual multipliers checked

symbolically in k and delta_0)

Constraints: ell, b >= 0, l_x >= 0, M + ell <= 1, and as stated per column. Every value below is computed by tower_template.wall and equals its closed form.

kpolePart I balanced 1 - 1/(2k)paper geometry 1 - 3/(4k)dual length only 1 - 2/kfloor, paper bin 1 - 25/(32k)floor, limit 1 - 4/(5k)z = 1/k in region two
111/21/4(formal)(formal)(formal)yes
21/23/45/8039/643/5yes
31/35/63/41/371/9611/15yes
41/47/813/161/2103/1284/5yes
51/59/1017/203/527/3221/25yes
61/611/127/82/3167/19213/15yes
71/713/1425/285/7199/22431/35no
81/815/1629/323/4231/2569/10no
121/1223/2415/165/6359/38414/15no
1001/100199/200397/40049/50127/128124/125no

3.3 The order k = 1 (derived arithmetic; the reading is inferred)

At k = 1, z* = 1 and the balanced geometry gives c = -1/4, low exponent 1/4, sigma_0 = 1/2. There is no twist, so every frequency is principal and the probe is the signal itself: Z^(-1/4) times a smoothed sum of mu(n) eta(n) of length Z. The direct bound Z^(1/4) it asks for is square-root cancellation in that Moebius sum, which for eta = 1 is Littlewood's condition M(x) << x^(1/2 + epsilon), equivalent to RH (Littlewood 1912; Titchmarsh, The Theory of the Riemann Zeta-Function, section 14.25; classical, quoted, not rechecked here). The floor-wall multipliers fail at k = 1 (y3 < 0), so k = 1 is outside the walls' proof, as it must be. The reading is that the template is a one-parameter family whose k = 1 member is a restatement of RH and whose k = 6 member is the paper; moving k toward 1 is moving toward the restatement, which supplies no estimate.

3.4 The price of 1/2 (derived, exact LPs)

Three generic constraints meet at the floor corner (ell, M) = (1/5, 4/5): the dual length M + ell <= 1 (D), the floor rows at delta_0 -> 0 (F, high side), and the direct bound's loss condition (L, low side), which hunt #134 reads either as "only the unrescaled summand lossless", M >= (1 + 3 ell)/2 (total accounting, tight at the same corner), or as "every summand lossless", M - 2 ell >= 1/2 (per-summand, the paper's own corner, which gives 1 - 3/(4k) and is higher still). How far they would have to be relaxed, by a common eps in powers of Z, for some geometry to reach sigma_0 = 1/2, i.e. M - 2 ell = 2 - k:

kD and FF alone (D exact)D alone (F exact)D, F, L (total accounting)D, F, L (per summand)
21/81/61/22/71/2
37/167/127/413/2
43/41 (only at ell = 1, M = 0)312/75/2
517/16infeasible17/417/77/2
611/8infeasible11/222/79/2
82infeasible832/713/2
124infeasible1352/721/2

Closed forms (each checked against its LP for k = 2..12): max((5k - 8)/16, (k - 4)/2); (5k - 8)/12 for k <= 4; 5k/4 - 2; (5k - 8)/7; k - 3/2. Every column increases with k. The two columns without L are relaxations of the template, not readings of it: with L imposed in either reading, a gain on the floor rows alone moves nothing (the wall stays 1 - 4/(5k) under total accounting and 1 - 3/(4k) per summand), because L is tight at the same corner. Improving F and L together by Z^g gives 1 - (4 + 3g)/(5k) up to g = 2 and the dual-length wall 1 - 2/k after it; a dual length longer by Z^e with F exact gives 1 - (4 + 2e)/(5k) (derived, checked against the LPs). In words: at the paper's order 6, reaching 1/2 needs all three generic constraints relaxed by 22/7 (total accounting) or 9/2 (per summand) in powers of Z, more than the whole range of the geometry, and no gain on the floor rows and the direct bound together takes the template below the dual-length wall 2/3. At k = 2, for which no system exists, the joint price is 2/7 or 1/2.

3.5 The first test that could fail

test_tower_hypothesis_fails_sigma0_increases_to_one encodes the mission's hypothesis in its negation: for 200 random rational admissible geometries and k = 1..64 the increment is the closed form above and positive, 1 - sigma_0(k) <= 2/k, sigma_0 > 1/2 from k = 5 on, and sigma_0(10^6) > 0.999997. It would have failed had the pole entered the template in any way that made the signal stronger with k (the planted k/36 reading does exactly that and is caught by the comparison at k = 7). It passed.

4. Which estimate fails at large k

None has to: the signal's density 1/k ends the tower before any estimate is reached. For the record, the candidates the mission named and the others the template holds:

5. The small orders, the only useful direction

system (hunt #136's labels)ktemplate floor (limit)status
S2: cubic theta, quadratic twist23/5no scalar Euler identity (hunt #136 referee, committed b6c4972a8, REFEREE_W1.md section 3: gamma_2 gamma_3 has alpha-exponent 1/3)
S3: classical theta over Q(i), quartic twist44/5theta supported on squares: no squarefree c, no 1/L (same, exact through t = 4)
S1: cubic theta, cubic twist311/15the referee finds a scalar factorization L(x, eta)/L(2x, eta^2) at u = 1 (disagreeing with the probe lane's reading); its reciprocal factor cannot fire: its poles sit at x = rho/2, real part below 1/2, under every k = 3 wall (derived here on the referee's factorization)
S4: biquadratic theta, quartic twist44/5L1 undetermined over Q(i); fails over F_13[T] (hunt #148, uncommitted)
S5: quintic theta over Q(zeta_5)521/25L1 undetermined (hunt #136 probe lane, uncommitted)
S0: the paper, cubic theta, sextic twist613/15the only realized system; its assembly's optimum 0.874958 (hunt #134); public records near 0.8748 (hunt #136)

So the direction that lowers the abscissa has no working system below k = 6, and even a working k = 2 system with perfect row counts would stop at 3/5.

6. The function-field analogue

Hunt #148 (ff_probe, branch hunt/ff-probe, files uncommitted at the time of reading) built the F_7[T] transplant of the cubic probe and checked Lemma 7.1 exactly there, and found the biquadratic case unusable (section 4). What that settles for this mechanism:

7. The distinguishing step and the rival gate

7.1 The step

The continuation criterion (Proposition 2.1) is a shared lemma: hunt #120 showed it goes through for any function whose reciprocal is bounded on Re s >= 2. The Euler product is consumed where its hypotheses are manufactured. In the probe, the theta coefficient at a squarefree index is gamma_2(c) = mu(c) alpha(c) G(c)/gamma_1(c) (line 3967), so the target enters the principal row through mu(c) eta(c) and, by the scalar Euler identity (lines 4043-4047), as 1/L^S(x, eta) times a correction H that the criterion needs within 1/2 of 1 (line 413). The target enters the row linearly through eta(A) at the completed index (hunt #136 referee, section 2), at every order k. So the step, in the form that can be tested on any coefficient sequence f, is:

(E_k) The principal row's dependence on the target is R_f(s) = sum over squarefree n of mu(n) f(n) n^(-s), and the criterion needs R_f = H_f / L_f with sup over Re s > sigma_0 of |H_f - 1| <= 1/2, for some finite deletion set.

It does not depend on k. For a linear combination f = c1 eta1 + c2 eta2 of two Euler products, linearity gives R_f = c1 H1/L1 + c2 H2/L2, whose poles are the constituents' zeros, never the combination's. Below, the constituents' corrections H_i are set to 1 (over Q, for characters, exactly) or computed (degree 2). For unitary characters the paper's full correction at the principal point converges absolutely from Re x > 2/3 by the closed form's monomials (hunt #148 derived this for F_7[T]; the number-field monomials are the same, inferred; principal_correction_abscissa pins the arithmetic), which covers the DH points used here. For the degree-2 constituents of Epstein (1,1,6) and for W_a the paper writes no identity; section 7.5 says how unitarity enters there.

7.2 Control: zeta and Dirichlet L-functions

f completely multiplicative: R_f = 1/L_f exactly, H_f = 1. Measured control: the squarefree Moebius sum to n = 20000 at s = 2 equals 1/zeta(2) to 6.9e-8, inside its tail bound 5e-5.

7.3 Davenport-Heilbronn (fails, at every k)

f = c1 chi + c2 chibar with chi mod 5, chi(2) = i, c1 = (1 - i kappa)/2, from zeta.epstein.

7.4 Epstein (1,1,6), discriminant -23 (fails)

Z_Q/2 = (zeta_K + 2 L_psi)/3 with K = Q(sqrt(-23)) and psi the cubic class character, so R_f = (H_1/zeta_K + 2 H_psi/L_psi)/3 with H_1, H_psi the degree-2 corrections (absolutely convergent on Re s > 1/2), computed over p <= 10^4 from exact representation counts. At rho = 0.9532604748 + 16.2902157204i (measured, dps 25): |Z_116(rho)| = 3.1e-29; |zeta_K(rho)| = 1.45600 by the lattice route (Z_116 + 2 Z_213)/2, agreeing with zeta(rho) L(rho, chi_-23) by the Hurwitz route to 5.2e-27; |L_psi(rho)| = 0.72800; |H_1| = 1.4163, |H_psi| = 1.0963; the probe-visible reciprocal is finite, |R| = 0.70349; H_E = (Z_116/2) R has |H_E| = 1.1e-29 and |H_E - 1| = 1.0000. The contraction fails for every sigma_0 < 0.9533, past 7/8: the step refuses this rival exactly where hunt #120 located the refusal for discriminant -15.

7.5 W_a = zeta(s + 1/4) zeta(s - 1/4) (passes the step; held off by unitarity)

The coefficients a(n) = n^(-1/4) sigma_(1/2)(n) are multiplicative, so R_W = H_W / W_a with H_W = prod over p of (1 - p^(-2s)/((1 - p^(1/4 - s))(1 - p^(-1/4 - s)))), absolutely convergent on Re s > 1/2. Second route: at s = 3 the squarefree Moebius sum to n = 20000 equals H_W/W_a to 1.0e-10 (measured). At the zero s_1 = 3/4 + 14.1347251417i, |W_a(s_1)| = 1.7e-21, and over p <= 10^5 (omitted factors within 0.0064 of 1): |H_W - 1| = 0.236 with nothing deleted, 0.0017 with p <= 10 deleted, 0.0024 with p <= 100 deleted (measured). The pass is uniform, not just at the zero: for Re s >= sigma > 1/2 each omitted factor is 1 + e_p with |e_p| <= p^(-2 sigma)/((1 - p^(1/4 - sigma))(1 - p^(-1/4 - sigma))), so deleting the primes up to P makes sup |H_W - 1| at most exp(c(P) sum_{n > P} n^(-2 sigma)) - 1, which is below 1/2 for P large enough at every sigma > 1/2 (for instance below 0.26 on Re s >= 3/4 with P = 100, summing crudely over all integers; derived). W_a passes (E_k) on every half-plane Re s > 1/2 + delta: its probe-visible reciprocal has the pole at its off-line zero that the criterion needs (this tests the bare Moebius identity; the paper writes its full identity only for unitary GL(1) targets, and the cube-completion terms of a degree-2 target are not computed here). What keeps the template away from W_a is unitarity, which the paper uses twice: the direct bound uses |eta| = 1 through the mean square of the theta row, and the local identity's parameters rho, a_p, b_p have absolute value one (line 3870). For the GL(1) factor zeta(s - 1/4), whose character n^(1/4) is not unitary, both shift by exactly 1/4, as a change of variables (derived): the direct bound and the target rise by 1/4, and the region where the principal correction converges absolutely moves from Re x > 2/3 to Re x > 11/12 (its term a_p^2 Q^(4 - 6x - 6z) at z = 1/6 grows by Q^(6/4)). For the degree-2 placement the same rise of 1/4 in the direct bound is inferred (coefficients up to d(n) n^(1/4)). W_a's zeros sit at 1/2 + 1/4, so they are within reach only if sigma_0 < 1/2, which no wall allows (the best is 3/5 + 1/4 = 17/20 > 3/4). W_a is a rival that lacks a hypothesis the argument uses, not a counterexample; what it shows is that the tower needs unitarity at every k, beside the Euler product.

7.6 What the gate says

Read two-sidedly (docs/08 section 4.3): DH and Epstein (1,1,6) violate the conclusion and fail the step that uses the Euler product, at every k, so they are not counterexamples and the step is genuinely distinguishing. W_a satisfies the step and violates the conclusion's analogue, but lacks unitarity, which the direct bound and the local identity use at every k. No rival passes every hypothesis. The gate does not bear on the tower's failure, which is internal to the template.

8. Known obstructions engaged, and what differs from refuted forms

9. Disposition

Restricted class obstructed. The class: probes in which the target is twisted by a family of nontrivial power-residue characters of order k >= 2 (so the principal frequencies are the k-th powers and the comparison pole is z* = 1/k <= 1/2), whose signal, direct bound, dual length M + ell <= 1 and floor rows keep the paper's forms. The proof: the LP of section 3.2 with its dual multipliers (derived, symbolic in k, self-reviewed). That its hypotheses apply to such probes is the inferred reading of section 2.1. Within the class the tower premise is refuted (sigma_0 increases to 1) and 1/2 is unreachable (sigma_0 >= 3/5). Outside the class nothing is claimed: a probe whose principal frequency set had density above 1/2, or whose dual length or floor rows were handled differently, is not covered.

10. The furthest true statement reached

In the order-k template, for every k >= 2 and every admissible geometry, sigma_0(k) = 1 - 1/k + (M - 2 ell)/(2k) >= max(1 - 2/k, 1 - 4/((5 + 6 delta_0) k)) >= 3/5, with 3/5 attained only at k = 2 in the limit delta_0 -> 0, at (ell, M, b) = (1/5, 4/5, 0); and no common gain on the floor rows and the direct bound's loss condition takes it below the dual-length wall 1 - 2/k; sigma_0(k) is strictly increasing in k and tends to 1; the formal order k = 1 gives 1/2 exactly, where the direct bound is Littlewood's RH-equivalent Moebius bound.

Grade: derived (exact, symbolic in k, self-reviewed) on cited formulas, with the k-reading and the sufficiency of M + ell <= 1 inferred; composite grade inferred. Beside it, at the rival gate: the step (E_k) is k-independent; DH and Epstein (1,1,6) fail it at their zeros (measured), DH for every finite deletion set by Saias and Weingartner (cited, with derived steps); W_a passes it (measured) and is held off by unitarity (inferred), a shift of exactly 1/4 (derived).

11. Next step

The tower is closed inside its class, and its best member (k = 2) stops at 3/5 even with perfect row counts, so as a route to RH this mechanism has no next construction step that the template contains; continuing it is the owner's call. Section 3.4 prices the generic doors: at the realized k = 6, 1/2 needs the dual length, the floor rows and the direct bound's loss condition all relaxed by at least 22/7 in powers of Z, and no improvement of the floor rows and the direct bound together gets below 2/3 without a longer reflected dual. So the next step is not an RH step. The one decidable step left is a half-plane step, and it belongs with hunt #136, which owns the half-plane: since the floor rows and the loss condition are tight at the same corner, any attempt below 13/15 must improve both at once, for instance a mean value over the row family in place of the floor rows' pointwise treatment (R = 1, each row at its full size; Blomer, Goldmakher and Louvel's Theorem 1.3 applied to the floor rows' Moebius polynomials is the obvious candidate) together with a row-norm lemma whose second-branch loss (1 + 3 ell' - 2M')/4 (line 8306) is smaller. The exact LP of section 3.2 then prices the pair, 1 - (4 + 3g)/(5k) for a common gain Z^g. Recorded here as the hand-off; the mechanism as obstructed for RH.

12. Tests, commands, files

.venv/bin/python hunts/rh_moonshot/probe_tower/tower_template.py --paper --write
.venv/bin/python -m pytest -q -n0 hunts/rh_moonshot/probe_tower/test_probe_tower.py
.venv/bin/python -m pytest -q -n0 -m "not slow" hunts/rh_moonshot/probe_tower/test_probe_tower.py

test_probe_tower.py: 23 fast tests (citations, the k = 6 reproduction, both signal routes for k = 1..40, b-freeness, the line 15729/15732 transcription, the floor closed form, the symbolic identities, the tower's direction, the k = 1 endpoint, the walls and their dual multipliers, the best order, the price of 1/2 in five modes, the relaxed walls of the doors, region two, the S1 remark, the W_a shift and the 2/3 and 11/12 correction abscissae, four planted faults, the committed report and this page's quoted numbers against the code, the lexical rules) and 6 slow ones (DH at its zero, the DH Moebius-sum route, the DH 7/8-line scan near t = 85, Epstein (1,1,6) at its zero, W_a at its zero, the W_a Moebius-sum route); 29 in all, all passing (RUNS.md). Planted faults: a pole read as k/36 (passes k = 6, reverses the tower), the floor rows dropped (the k = 2 wall falls from 3/5 to 0), a Gram term held at 1/12 for every k (sigma_0 starts depending on b), a perturbed dual multiplier (the identity breaks). RUNS.md has the run manifests.

13. Sources, and what was searched

The doors

The page measures a ceiling of a construction family, so it owes this section. Candidate status: the walls of section 3.2 are lower bounds for the template's abscissa, proved by LP duality; parameter range k >= 2, ell, b >= 0, l_x >= 0, M + ell <= 1, delta_0 >= 0; information class below; proof status derived on an inferred reading, unreviewed.

Active constraints at the optimum

Ranked by what relaxing them buys toward 1/2 (section 3.4):

  1. The comparison pole z* = 1/k (the density of k-th powers among the frequencies). It scales the whole distance to 1: 1 - sigma_0 = (2 - m)/(2k). Its shadow price at the paper's geometry is d sigma_0/d z* = -(h - b/2) = -3/4. Lowering k is the largest lever; raising it, the tower, is the wrong sign.
  2. The floor rows and the direct bound's loss condition, together. The floor rows C_0(k) + (1 + ell - M/2) delta_0 <= 0 (multiplier y1 = 12/5 in the D-F system) and the unrescaled-summand condition M >= (1 + 3 ell)/2 are tight at the same corner, so neither moves the wall alone; a common gain of Z^g moves it to 1 - (4 + 3g)/(5k), down to the dual-length wall at g = 2. Price of 1/2 with the dual length: 2/7 at k = 2, 22/7 at k = 6 (total accounting); 1/2 and 9/2 per summand.
  3. The dual length M + ell <= 1 (multiplier y2 = 4/5 in the D-F system; a longer dual by Z^e moves the wall to 1 - (4 + 2e)/(5k)). Alone it bounds sigma_0 by 1 - 2/k, above 1/2 for k >= 5.

The frozen-constant inventory

constantvaluewhat relaxing it tradestrade shape
character order k6 (realized), any k >= 2 herethe whole theta construction (L1-L3); larger k weakens the signalgenuine; the useful direction (smaller k) has no system
floor bin delta_01/50the floor wall from 1 - 25/(32k) to 1 - 4/(5k); needs Euler region one below 51/100genuine, small
slot length ell, total length M, offset bfree, optimum (1/5, 4/5, 0) at the floor cornerlower m = M - 2 ell against the floor rows, the loss condition and the dual lengthexhausted by the LP
row-norm second-branch loss (1 + 3 ell' - 2M')/4held (line 8306)tight at the floor corner with the floor rows; must improve together with themgenuine, outside the template
contour Re z = 17/50heldcancels at d = hnone
Euler region two z_r >= 33/200heldcontains z = 1/k only for k <= 6binding for the tower from k = 7, needs an identity that does not exist
large-sieve exponent (MN)^(2/3)n-free (BGL)row counts onlynone for the walls

The information class