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Library · hunts/seven_eighths_pin/RESULTS.md

Results: which step of the quasi-Riemann argument fixes the number 7/8

5,989 words · 495 lines · source

Hunt #139 (opened as #134), 2026-10-16. Status: answered within its stated scope; unreviewed by any person. Grades: cited (a line of the paper, quoted and checked against the pinned file), derived (algebra done here from cited formulas and checked in exact rational arithmetic by test_seven_eighths_pin.py), inferred (a reading of a lemma's proof that no computation here checks). A composite claim takes the grade of its weakest step. Nothing here is a statement about RH, and nothing here checks the paper's lemmas: they are taken as cited inputs, at the exponents the paper proves them with.

Source: github.com/openai/math at adc7f1241b42e322a6451854ab7e4b4c146bf78a, preprints/The-Quasi-Riemann-Hypothesis-September-30-2026/build/paper.tex, 16,677 lines, sha256 42a5ee0febca59fd1def55cfd6c6808c322ef4237d7726303ea52f711deac6a3. Line numbers below refer to that file. probe.py --paper PATH checks that each of the 39 cited snippets sits on its stated line (all 39 do).

Landing note, 2026-10-21. Opened as hunt #134 and renumbered #139 at landing, because #134 on main is gauss_positivity and #136 to #138 are taken by other open hunts and landings. The prior-art search this page had not run was run at landing and extended the same day to the three works its first source names and to the follow-ups' own manuscripts (section 10 lists what was read, with commits). Much of this page was public before the hunt opened on 2026-10-16, so it was derived here independently and is not novel:

  • a model computation by tomoto0 (7 October 2026) has the target formula of Summary

item 1 with its ζ_F(6z) pole, the floor-row ceiling 13/15 of Summary item 5 at the same corner, a geometry optimum near 0.87496 with the zero-detected rows binding (the two ends of section 6), and on a grid the worst point and margin of Summary item 4 at the paper's geometry;

  • J. Guo and B. Liu (8 October 2026) give the exact optimum of the re-optimized geometry

of Summary item 3 and section 4, σ* = (1507 − 2√921)/1653 ≈ 0.8749570698, and the further gain of section 7's tied capacity; Guo derives the binding bin δ* = (49 − √921)/48 at x = 1/2 from the vanishing coefficient of the offset;

  • the total accounting of section 3, marked inferred below, is a proof step on the line

M + ℓ = 1 in Z. Gao's draft (7 October) and in Guo's and Argonaut Math's papers (8 October).

Section 10 also records two consequences checked at landing against this hunt's own formulas (the exact bound 0.874942 is valid but loose, and the scan optimum 0.874958 is a grid reproduction of σ*), what was not found in the sources read, and one disagreement with tomoto0 over the slope α. The rest of this page is as the hunt wrote it.

Summary

  1. The target is set by the direct ("low") bound, and both stages lie on one line. The paper continues 1/L past a hypothetical zero by comparing a smoothed sum with a Mellin integral Z^{C(s)}. The target is the point where the direct bound on that sum equals C(σ₀). Written in the free geometry (ℓ the total prime-slot length, M the two averaging lengths together, b their offset), that point is σ₀ = 1 − h/6 + b/12 = 5/6 + (M − 2ℓ)/12 (derived). Part I (no slots, M = 1) gives 11/12; Part II (ℓ = 1/6, M = 5/6) gives 7/8. On the paper's line M + ℓ = 1 this is σ₀ = 11/12 − ℓ/4: every unit of slot length lowers the target by a quarter. The 1/6 in h/6 is the pole at z = 1/6 of the sextic factor ζ_F(6z), not the slot length (cited, lines 5586, 8641).
  2. The paper's geometry is the corner of two direct-bound conditions, and one of them alone gives exactly 7/8. The reflected dual length must not exceed the row length, M + ℓ ≤ 1 (line 8246, used there as an equality). The row-norm lemma has a second-branch loss (1 + 3ℓ' − 2M')/4 (line 8306); asking for no loss in every rescaled summand means M − 2ℓ ≥ 1/2, hence σ₀ ≥ 5/6 + 1/24 = 7/8 for every choice of ℓ, M and b (derived). The two lines meet at ℓ = 1/6, M = 5/6, which is the paper's geometry.
  3. That second condition is stricter than the argument needs, but the high side then binds at the same place. Each rescaled summand also gains Z^{−d} (line 8631), which absorbs the loss; only the unrescaled summand must be lossless, M ≥ (1+3ℓ)/2 (inferred). Under that accounting the direct bound alone would allow targets down to 13/15. The high side does not: the paper's endpoint inequality (Lemma "Compensated endpoint certificate", lines 15994 to 16072) fails below the following, with the paper's row counts held fixed.
  4. Exact bound, every geometry with M + ℓ ≤ 1 and b ≥ 0: σ₀ ≥ 5655673/6464057 ≈ 0.874942 (derived; one witness point δ = 223/576, x = 1/2).
  5. With the paper's Gram condition b ≤ 3(M − 2ℓ)/8 added: σ₀ ≥ 44117/50422 ≈ 0.874955 (derived; witness δ = 7/18, x = 1/2).
  6. Float optimum of the scan: 0.874958 at b ≈ 0.12, ℓ ≈ 0.166836 (measured). The paper's (ℓ, b) = (1/6, 1/8) is within 1.7 × 10⁻⁴ in ℓ and 4.2 × 10⁻⁵ in the target of the best its own high side allows.

So 7/8 is the corner of the direct bound, and the high side's optimum sits 4.2 × 10⁻⁵ below it. The number is not slack left on the table: re-choosing the geometry inside this assembly can gain at most 5.8 × 10⁻⁵.

  1. The binding rows are those whose twisted L-functions have a zero near real part 0.69 (δ = 2a − 1 ≈ 0.39) and whose prime-slot polynomials are as large as that zero allows (x = q/δ = 1/2). At the paper's point the margin there is exactly −E_* = 7/30672 ≈ 2.3 × 10⁻⁴, about twice the paper's printed lower bound 49/440640 (derived). The mechanism: in the high exponent the slot amplitude costs +qℓ and the constant C₀ = −1/4 + 5ℓ/4 + b/6 grows with ℓ, while the moment lemmas' row-count gain is capped by their capacities and does not grow with ℓ (cited formulas, lines 15192 and 15729; the reading that the counts are ℓ-free is cited at 15192 and inferred for the lemmas behind it).
  2. Even perfect row counts stop at 13/15. Rows with no zero beyond the floor are counted in full (exponent R = 1), which no lemma can improve, and they need C₀ = 1/2 + ℓ/2 − 3M/4 + b/6 ≤ 0. Together with M + ℓ ≤ 1 the smallest target is 13/15 at ℓ = 1/5, M = 4/5, b = 0, where the unrescaled-summand condition is tight too (derived). Scaling the row-count excess R_* − (1 − δ) by λ moves the best target almost linearly from 0.874958 (λ = 1) to 13/15 (λ = 0) (measured, section 6). This floor holds for this assembly's three forms (direct bound, Mellin signal, high-exponent shape), not for the method family.
  3. What does not fix 7/8 (section 7): the Euler regions and the contraction of H_η (7/8 is plugged in; they hold down to about 2/3); the contour Re z = 17/50 (it cancels at d = h); the principal margins (contour choices); the 11/12 input (it only caps δ ≤ 5/6; the α = 5/6 in the row counts is the sextic amplification slope (1 + 5r)/6, not the bootstrap); Lemma plain's κ ≥ 3/4; the slot supply (a lower bound only).

1. What was read

The final section, "The seven-eighths bound" (lines 15495 to 16466), in full, and the Part II setup (6807 to 6918), the compensated low estimate (8559 to 8651), the row-norm lemma's second branch (8196 to 8334), the definition of the stage data (5586) and the no-slot inverse count (15276 to 15310) directly. Four separate readings, each writing verbatim formulas with line numbers to a report and checking its own arithmetic, covered the row counts (14985 to 15495 and the statements of Lemmas marked, plain and the detector propositions), the shared analytic lemmas (5460 to 6700, including the Part I conclusion), the probe geometry (3313 to 3723, 6807 to 6918, 8061 to 8651) and the Euler regions and moment hypotheses (3723 to 4201, 8651 to 9209, 9209 to 14985 for hypotheses only). Those reports are model readings; every number this page uses from them is either re-derived in probe.py or marked inferred. The proofs of the moment lemmas (Sections 9 to 12 of Part II, about 5,800 lines) were not checked.

2. The target on the direct-bound side

Cited:

Derived (exact, test_target_closed_form): with l_x = (M − b)/2, l_y = (M + b)/2,

σ₀ = 1 − h/6 + b/12 = 5/6 + (M − 2ℓ)/12,

so b cancels, σ₀ = 11/12 − ℓ/4 on M + ℓ = 1, and the two stages are the points (ℓ, M) = (0, 1) and (1/6, 5/6) on the same formula.

3. The paper's corner

Cited: line 8246, "Since M'+ℓ'−1=−3d", shows the reflected dual length T_d stays below the row length; with general parameters the same subtraction leaves an extra M + ℓ − 1, so M + ℓ ≤ 1 suffices (derived from the cited display). Line 8306 gives the second-branch energy M' + (1 + 3ℓ' − 2M' − 2Δ_H + θ_N)/4, with M' = M − 2d and ℓ' = ℓ − d for a summand rescaled by Z^d (the paper's own substitution at M = 5/6, ℓ = 1/6 gives its (d − 1/6)/4). The general loss is therefore ((1 + 3ℓ − 2M + d)/4)₊ for 0 ≤ d ≤ ℓ.

4. The high side and its endpoint inequality

Cited: the high exponent E(d) = a − 7/8 + h(17/50 − 1/6) − a l_y − (1−a)ℓ − (δ/2 − q)ℓ + d(R + δ/2 − 17/50) with C₀ = −1/48 (lines 15729 to 15734); the row counts D_x = 3 − 17x/9, P_x = (2 − 8x/9)(1 − x) (line 15192), R_* = 1 − δ + (α − δ)δP_x/(2𝒥) with 𝒥 = (α − δ)D_x + δP_x (line 16019); the certificate −E_* ≥ 49/440640 (line 16000) and its completed-square identity (line 16048); and the requirement E_actual(h) − Δ ≤ −49/440640 − (51/64)Δ (line 16101).

The requirement is relative to the hypothetical zero, Δ = β* − 7/8 > 0, and the capacity allowance hΔ/4 is smaller than Δ, so what the argument needs is −E_* ≥ 0 at every (δ, x); the printed 49/440640 is room on top. As Δ → 0 the condition is necessary for this assembly's bound.

Derived, with M free:

−E_* = (−1/2 − ℓ/2 + 3M/4 − b/6) + δ(ℓ + b)/2 − ℓxδ − (h/2)·K(δ, x), K = (α − δ)δP_x/𝒥, h = 1 + ℓ − M/2 + b/2.

The offset is bounded below by a hypothesis of the Gram bound, P_a = Y'²/Q ≥ 1 (Prop. probe-gram, line 8345), and P_a = Z^b up to fixed constants (line 8591), so b ≥ 0 (cited). This matters: at the witness below, smaller b helps, so b < 0 would weaken the bound; it lies outside the lemma as stated and would change the direct bound's form (P_a^{1/12} no longer below the other Gram terms), which is not explored here. At fixed (δ, x), both −E_* and σ₀ are affine in (ℓ, M, b). Along a line of constant σ₀ and b, d(−E_*)/dℓ = 1 + δ(1/2 − x) > 0 (test_constant_target_slope), so the best geometry has M + ℓ = 1. There −E_* decreases in ℓ, and each fixed (δ, x) gives an exact lower bound on σ₀ by a two-variable linear program:

boundvaluewitnessuses
every geometry, M + ℓ ≤ 1, b ≥ 05655673/6464057 ≈ 0.8749417δ = 223/576, x = 1/2b-coefficient ≤ 0 there, so no upper limit on b is used
adding b ≤ 3(M − 2ℓ)/8 (Gram condition of Prop. probe-gram at d = ℓ)44117/50422 ≈ 0.8749554δ = 7/18, x = 1/2the Gram limit
float scan, best over b ∈ {0, 0.01, …, 0.18}0.874958 at b ≈ 0.12, ℓ ≈ 0.166836grid 1201 × 201measured only

The paper's own point has min −E_* = 7/30672 at δ = 79/204, x = 1/2 (derived; the completed square (4vδ − 79)² at v = 51 places it there).

5. The floor-row ceiling 13/15

Cited: the floor bin a = 51/100 uses no zero witness, count R = 1, and E(h) ≤ C₀ + (3/4)δ₀ = −7/1200 (line 15847). Derived: in general the floor rows give E(h) = C₀ + (1 + ℓ − M/2)δ₀ with C₀ = 1/2 + ℓ/2 − 3M/4 + b/6, and as the floor approaches 1/2 the condition becomes C₀ ≤ 0. Rows counted in full cannot be counted better, so this survives any improvement of the moment lemmas. Minimizing σ₀ = 5/6 + (M − 2ℓ)/12 subject to C₀ ≤ 0, M + ℓ ≤ 1, b ≥ 0 gives the infimum 13/15 at ℓ = 1/5, M = 4/5, b = 0, where C₀, the dual-length slack and the unrescaled-summand slack are all zero (test_floor_corner_is_thirteen_fifteenths, test_no_geometry_beats_the_floor_corner).

6. How much better row counts would buy

Scaling the excess R_* − (1 − δ) by λ and re-optimizing (ℓ, b) on M + ℓ = 1 (still optimal for every λ, since the constant-target slope does not involve K), float scan:

λbest ℓbest btarget
1 (the paper's counts)0.1668360.120.874958
0.750.1752450.100.872856
0.50.1836000.070.870767
0.250.1918640.040.868701
0 (ideal count 1 − δ)0.20000000.866667 = 13/15

The curve is close to linear, about 0.0021 per quarter of the excess removed (measured).

7. What does not fix 7/8

8. Controls

9. Limitations and kill conditions

10. Prior art

As written on 2026-10-16: Not searched. This is a reading of a two-week-old preprint's internal constants; the paper itself does not say which inequality fixes 7/8, and docs/38 records that nobody here had read past its section 3. Original to this laboratory as a reading; whether anyone else has published the same observation is unknown.

Searched 2026-10-21, at landing. Searched: the follow-up that main already cites in hunts/qrh_nonresidue/RESULTS.md, J. Guo's github.com/aster2024/openai-math-followups, directory zero-free-beyond-7-8 (its README as of commit 5750cc81e489, 9 October 2026, unchanged at the repository's head on 2026-10-21); the arXiv abstract of B. Liu, arXiv:2610.12234 (v1 8 October, v2 12 October 2026); and one web search for the Xu and Sang figure that hunt #136 records. No paper's proofs were read. Found:

Extended 2026-10-21, the same day. The first search stopped at Guo's README, whose related-work paragraphs name three more works, and it read none of the follow-ups' own manuscripts. Read in the extension, as data, with the pinned paper.tex (sha256 as above) at hand for the cited lines:

Liu's note itself was not read, only its abstract, and no proof was checked. Every translation below between this page's variables and a source's is pinned in exact arithmetic by the block of tests just before the landing checks in test_seven_eighths_pin.py; the sources' own numbers are cited, not re-derived. Found:

These were derived here independently (the hunt read only the paper, RUNS.md) and are not novel.

The doors

The hunt locates a ceiling of one assembly, so this section is owed. Candidate status: the target 7/8 is the corner of the direct bound, and the high side's optimum is 0.874958 (measured) with exact lower bound 0.874942 (derived) over every geometry, with the paper's row counts; parameter range ℓ, M, b ≥ 0 with M + ℓ ≤ 1; proof status: exact arithmetic on transcribed formulas, unreviewed.

Active constraints at the optimum

Ranked by what relaxing them buys:

  1. The endpoint inequality at δ ≈ 0.39, x = 1/2. Zero margin at the optimum. Its shadow price: at the robust witness ∂(−E_*)/∂ℓ = −6464057/4850304 ≈ −1.333 on M + ℓ = 1, and ∂σ₀/∂ℓ = −1/4, so each 10⁻⁴ of margin added there buys about 1.9 × 10⁻⁵ of target. Removing a fraction of the row-count excess buys about 0.0083 per unit (section 6), down to 13/15.
  2. The direct-bound corner M − 2ℓ = 1/2 (per summand) and M + ℓ = 1. Tight at the paper's geometry. The first is a bookkeeping choice that total accounting removes, but removing it buys nothing while (1) binds.
  3. The floor rows, C₀ ≤ 0. Slack 1/48 at the paper's point; binds only once (1) is gone, at 13/15.
  4. The slot supply ℓ/h > 7/37. Slack 23/1443; a lower bound, never binding.

The frozen-constant inventory

constantvaluewhat relaxing it tradestrade shape
slot length ℓ1/6lowers the target by ℓ/4; raises C₀ by 5/4 and the amplitude cost qℓgenuine, already at its optimum to 1.7 × 10⁻⁴
offset b1/8appears in C₀ (+b/6) and helps at δ > 0 (+δb/2); optimum ≈ 0.12genuine, flat near the optimum
total length M5/6lower M lowers the target 1/12 per unit and costs the high side 3/4 per unitgenuine, the corner is optimal
contour Re z17/50cancels at d = h; matters only for intermediate rows, allowed roughly (49/150, 0.35) (inferred, second reading)none for the target
principal contoursRe w = 19/20, Re z = 33/200margins m_w, m_z onlynone
floor51/100lower floor shrinks the floor-row exponent but needs witnesses nearer 1/2genuine, slack 7/1200
capacity coefficient4/9 = 1/(3κ₀)follows the target; tied, it moves the optimum by < 10⁻⁶none here
amplification slope α5/6an input from the sextic large sieve; smaller α shrinks Kgenuine, outside this assembly
t-window, x-capt ≤ 3/2, x ≤ 1/2structural (capacities vanish at t = 3/2; x ≤ 1/2 from the bin rectangle)none

The information class